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0=98-6x^2
We move all terms to the left:
0-(98-6x^2)=0
We add all the numbers together, and all the variables
-(98-6x^2)=0
We get rid of parentheses
6x^2-98=0
a = 6; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·6·(-98)
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{3}}{2*6}=\frac{0-28\sqrt{3}}{12} =-\frac{28\sqrt{3}}{12} =-\frac{7\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{3}}{2*6}=\frac{0+28\sqrt{3}}{12} =\frac{28\sqrt{3}}{12} =\frac{7\sqrt{3}}{3} $
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